Sum of squares of first n natural numbers

Sum of square of n natural numbers 

here lower limit is 1 and upper limit is 10 .

That means sum of squares of n natural numbers ranging from 1 to 10 can be calculated as

\[\sum_{1}^{10} n^{2}   = \frac{n(n+1)(2n+1)}{6}  = 385\]

Similarly \[\sum_{1}^{100}n^{2} \]=  338350  and so on.

Hence 1+ 22 + 32 + 42 + ........................ + n    can be easily calculated using above formula.

where must belongs to some integer

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