Formula to evaluate a +b+c whole square

\[(a+b+c)^{2}=a^{2} +b^{2} +c^{2}+2ab+2bc+2ac =a^{2} +b^{2} +c^{2}+2abc(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}) \]

For example :   \[(1+2+3)^{2}=1^{2} +2^{2} +3^{2}+2*1*2+2*2*3+2*1*3 \]=36

                    here a=1 b=2 c=3

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