"If two sides of one triangle are proportional to two sides of another triangle and the angles formed by those sides are equal, then the two triangles are equiangular and hence similar".
In \[ \Delta les\]PAN and ITC
1) \[\frac{PA}{IT}=\frac{AN}{TC}\]
2) \[P \hat{A}N = I\hat{T} C\]
Then, \[A \hat{P}N = T\hat{I} C\]
\[A \hat{N}P = T\hat{C} I\]
\[\therefore \Delta PAN= \Delta ITC\]
