\[\sum_{n=1}^{n}n^4=\frac{n(2n+1)(n+1)(3n^2+3n-1)}{30}\]
Example \[\sum_{n=1}^{2}n^4=1^4+2^4=17\]
\[\sum_{n=1}^{3}n^4=1^4+2^4+3^4=98\]
Boundary condition n must be any natural number
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