If n is even then greatest value of \[ ^{n}C_{\frac{n}{2}}\]=\[\frac{n!}{((\frac{n}{2})!)^2}\]
For n=4 we get result as 6
if n is odd then the greatest value is given by \[ ^{n}C_{\frac{n+1}{2}} \] or \[ ^{n}C_{\frac{n-1}{2}} \]
for n =5 we get the answer 10 by putting in the formula
