What will be the output of the following Python code?l=[]def convert(b): if(b==0): return l dig=b%2 l.append(dig) convert(b//2)convert(6)l.reverse()for i in l: print(i,end='')

What will be the output of the following Python code?

l=[]def convert(b):
    if(b==0):
        return l
    dig=b%2
    l.append(dig)
    convert(b//2)
convert(6)
l.reverse()
for i in l:
    print(i,end="")

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What will be the output of the following Python code?l=[]def convert(b): if(b==0): return l dig=b%2 l.append(dig) convert(b//2)convert(6)l.reverse()for i in l: print(i,end="")

What will be the output of the following Python code?

l=[]
def convert(b):
if(b==0):
return l
dig=b%2
l.append(dig)
convert(b//2)
convert(6)
l.reverse()
for i in l:
print(i,end="")